- #1

- 492

- 0

[tex] g(x)=y+Dy+D^{2}y+D^{3}y+.................. [/tex]

D=d/dx, then this is equal to:

[tex] g(x)= \frac{1}{1-D}y [/tex] or inverting [tex] y=(1-D)g(x) [/tex]

although this should be the solution it seems too easy to be true..but is that correct?..thanks.